matlab双重求和 ∑∑[2sin(m*pi/2)*sin(n*pi/2)]/[1512.36(m^2+n^2)-(2pi*f)^2],m,n从0至100,结果含f
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我绘制的matlab图形是空白的 >> a=0:0.1:pi/2; >> L=5; >> M=L.*(1-cos(a))/sin(a).^2; >> plot(a,M)~
clc
clear all
syms f;
sum=0;
for m=1:2
for n=1:2
sum=sum+(2*sin((2*m-1)*pi/2)*sin((2*n-1)*pi/2))/(1512.36*((2*m-1)^2+(2*n-1)^2)-(2*pi*f)^2);
end
end
sum
望楼主采纳。
更改下颜色:
plot(a,M,'p')
%f(x)=sin^2(m/100)x,x属于[0,pi],m=403
%(1)-----------------
x=0:0.01:pi;
m=403;
f = sin(m*x/100).^2;
plot(x,f);
%(2)---------------
n=100;
x1 = 0:pi/n:pi;
x1 = x1 + pi/2*n;
x1 = x1(1:n-1);
f1 = sin(m*x/100).^2;
n=200;
x2 = 0:pi/n:pi;
x2 = x2 + pi/2*n;
x2 = x2(1:n-1);
f2 = sin(m*x/100).^2;
n=1000;
x3 = 0:pi/n:pi;
x3 = x3 + pi/2*n;
x3 = x3(1:n-1);
f3 = sin(m*x/100).^2;
%(3)--------------------------
m1 = (99*mean(f1)+199*mean(f2)+999*mean(f3))/(99+199+999);
disp('由2产生的函数值的平均值')
disp(m1)
%(4)-----------------------
xx = fsolve(@(x) sin(m*x/100)^2-m1,0.1);
disp('对于x解方程f(x)=均值')
disp(xx)
clc
clear all
syms f;
sum=0;
for m=1:2
for n=1:2
sum=sum+(2*sin((2*m-1)*pi/2)*sin((2*n-1)*pi/2))/(1512.36*((2*m-1)^2+(2*n-1)^2)-(2*pi*f)^2);
end
end
sum
望楼主采纳。